3(q-2)+q^2=q(q+3)-6

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Solution for 3(q-2)+q^2=q(q+3)-6 equation:


Simplifying
3(q + -2) + q2 = q(q + 3) + -6

Reorder the terms:
3(-2 + q) + q2 = q(q + 3) + -6
(-2 * 3 + q * 3) + q2 = q(q + 3) + -6
(-6 + 3q) + q2 = q(q + 3) + -6

Reorder the terms:
-6 + 3q + q2 = q(3 + q) + -6
-6 + 3q + q2 = (3 * q + q * q) + -6
-6 + 3q + q2 = (3q + q2) + -6

Reorder the terms:
-6 + 3q + q2 = -6 + 3q + q2

Add '6' to each side of the equation.
-6 + 3q + 6 + q2 = -6 + 3q + 6 + q2

Reorder the terms:
-6 + 6 + 3q + q2 = -6 + 3q + 6 + q2

Combine like terms: -6 + 6 = 0
0 + 3q + q2 = -6 + 3q + 6 + q2
3q + q2 = -6 + 3q + 6 + q2

Reorder the terms:
3q + q2 = -6 + 6 + 3q + q2

Combine like terms: -6 + 6 = 0
3q + q2 = 0 + 3q + q2
3q + q2 = 3q + q2

Add '-3q' to each side of the equation.
3q + -3q + q2 = 3q + -3q + q2

Combine like terms: 3q + -3q = 0
0 + q2 = 3q + -3q + q2
q2 = 3q + -3q + q2

Combine like terms: 3q + -3q = 0
q2 = 0 + q2
q2 = q2

Add '-1q2' to each side of the equation.
q2 + -1q2 = q2 + -1q2

Combine like terms: q2 + -1q2 = 0
0 = q2 + -1q2

Combine like terms: q2 + -1q2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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